SOLUTION: I am having trouble with a problem I cannot seem to figure out the next step on it. The problem goes as follows:
Rationalize the denominator and simplify.
The nth root is 7 r
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-> SOLUTION: I am having trouble with a problem I cannot seem to figure out the next step on it. The problem goes as follows:
Rationalize the denominator and simplify.
The nth root is 7 r
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Question 396715: I am having trouble with a problem I cannot seem to figure out the next step on it. The problem goes as follows:
Rationalize the denominator and simplify.
The nth root is 7 radical 8x^29/243x^8
I split the radical up betweent the top and bottom and then multiplied both sides by the bottom. I know those steps are correct, however, I do not know how to solve it from there.
nth root 7 radical 8x^29/nth root 7 radical 243x^8 times the top and bottom by the nth root 7 radical 243x^8.
Where do I go from here?
Don't split the radical up until you subtract the exponents of the x's
Now split it up:
Since the power of x is a multiple of 7 we can take
it out of the radical on top, divide the exponent 21
by the index of the radical 7 and get x3 which
we write in front of the top radical:
Since 243 = 35, we replace 243 by that:
We have 35 on the bottom, and
we need 37 so that it will come out of the
radical, so we multiply by
Multiply under the radicals:
Rewrite 8*9 as 72 and the denominator as just 3
Edwin
