SOLUTION: The expression
\frac{\sqrt[3]{8 h^{-2} s^{-4}}} { \sqrt[3]{ h^{6} s^{4}}}
equals kh^rs^t
where r, the exponent of h, is:
and t, the exponent of s, is:
and k, the leading coef
Algebra ->
Radicals
-> SOLUTION: The expression
\frac{\sqrt[3]{8 h^{-2} s^{-4}}} { \sqrt[3]{ h^{6} s^{4}}}
equals kh^rs^t
where r, the exponent of h, is:
and t, the exponent of s, is:
and k, the leading coef
Log On
Question 395752: The expression
\frac{\sqrt[3]{8 h^{-2} s^{-4}}} { \sqrt[3]{ h^{6} s^{4}}}
equals kh^rs^t
where r, the exponent of h, is:
and t, the exponent of s, is:
and k, the leading coefficient is: 2
I have worked it out and keep getting k as 2, which is correct, but I am also getting 2 as answers for r and t with the cubed root of hs left over. I can't seem to get it in the right format that they want. Answer by richard1234(7193) (Show Source):
