You can
put this solution on YOUR website! add and/or subtract and simplify the following radical expression.
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3Ö48 - 2Ö27 - 3Ö12
thanks for your time
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3Ö48 - 2Ö27 - 3Ö12
Break 48 down into primes: 48 = 8·6 = 4·2·2·3 = 2·2·2·2·3
Break 27 down into primes: 27 = 3·9 = 3·3·3
Break 12 down into primes: 12 = 4·3 = 2·2·3
Replace the radicands by their prime factorizations:
_________ _____ _____
3Ö2·2·2·2·3 - 2Ö3·3·3 - 3Ö2·2·3
Now group the factors under the radicals into pairs
of like factors as much as possible. (Note: if these
had been cube roots you would have grouped by threes
instead of by twos, and if they had been fourth roots
you would have grouped by fours, etc.)
_____________ _______ _______
3Ö(2·2)·(2·2)·3 - 2Ö(3·3)·3 - 3Ö(2·2)·3
Now each pair is a square and will come out in front of the radical
as a SINGLE factor.
Each of the (2·2)'s comes out in front of of the 1st and 3rd radicals
as a SINGLE 2 factor.
The (3·3) comes out of the 2nd radical as a SINGLE 3 factor.
So we have
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3·2·2Ö3 - 2·3Ö3 - 3·2Ö3
or
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12Ö3 - 6Ö3 - 6Ö3
_
Factor out Ö3
_
Ö3(12 - 6 - 6)
_
Ö3(0)
0
The answer is 0.
Edwin McCravy
AnlytcPhil@aol.com