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Algebra: Radicals -- complicated equations involving roots
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Question: Square root of 54y^10
54=9*6
y^10=y^5*y^5
Square root of 9*6 = 3*{6^1/2} or 3*{square root of 6}
Square root of y^10 = y^5
Therefore square root of 54y^10 = 3y^5{6^1/2}