SOLUTION: I am struggling with a distance formula problem that has radicands in the points. I am ok with doing the distance formula d=square root of (x2-x1)sq +(y2-y1)sq.
the points I am tr
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-> SOLUTION: I am struggling with a distance formula problem that has radicands in the points. I am ok with doing the distance formula d=square root of (x2-x1)sq +(y2-y1)sq.
the points I am tr
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Question 365082: I am struggling with a distance formula problem that has radicands in the points. I am ok with doing the distance formula d=square root of (x2-x1)sq +(y2-y1)sq.
the points I am trying to find the distance between are:
(4 square root of 2, 3 square root of 5) and (-2 square root of 2, 5 square root of 5) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! (4 square root of 2, 3 square root of 5) and (-2 square root of 2, 5 square root of 5)
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(4*sqrt(2),3*sqrt(5)) and (-2*sqrt(2),5*sqrt(5))
diffy = 2sqrt(5)
diffx = 6sqrt(2)
d = sqrt(92)
d =~ 9.59
