SOLUTION: Find the y - intercept and the vertex......y = x^2 - 3x -4....Thank you for your help much appreciated.

Hi,



Note: The general vertex form of a parabola,  (h,k) is the vertex



completing the square to put into the vertex form of a parabola

y = x^2 - 3x -4

y = x^2 - 3x + 9/4 - 9/4 -4

vertex form is:

y =1*(x - 3/2)^2 - 25/4

Vertex is (3/2, - 25/4)  a>0 Therefore parabola opens upward and vertex is the Minimum

y intercept is Pt(0,-4)