SOLUTION: Solve. 25(v + 1 )^2 -10 = 0 Can you help.....lost here.

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Question 358499: Solve. 25(v + 1 )^2 -10 = 0 Can you help.....lost here.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

If this correctly states your question:

25%28v+%2B+1+%29%5E2+-10+=+0++

Recommend expanding the (v+1)^2

25%28v+%2B+1%29%28v%2B1%29+-10+=+0++

25%28v%5E2+%2B+2v+%2B+1%29-10+=+0++

25v%5E2+%2B50v+%2B25-10+=+0++

25v%5E2+%2B50v+%2B+15+=+0++

5%28+5v%5E2+%2B10v+%2B+3%29+=+0++

And solving with Quadratic Formula




 
Solved by pluggable solver: SOLVE quadratic equation with variable


Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 5x%5E2%2B10x%2B3+=+0) has the following solutons:

  

  x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

  

  For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

  

  First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%2810%29%5E2-4%2A5%2A3=40.

  

  Discriminant d=40 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-10%2B-sqrt%28+40+%29%29%2F2%5Ca.

  

    x%5B1%5D+=+%28-%2810%29%2Bsqrt%28+40+%29%29%2F2%5C5+=+-0.367544467966324

    x%5B2%5D+=+%28-%2810%29-sqrt%28+40+%29%29%2F2%5C5+=+-1.63245553203368

    

    Quadratic expression 5x%5E2%2B10x%2B3 can be factored:

  5x%5E2%2B10x%2B3+=+5%28x--0.367544467966324%29%2A%28x--1.63245553203368%29

  Again, the answer is: -0.367544467966324, -1.63245553203368.
Here's your graph:

graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+5%2Ax%5E2%2B10%2Ax%2B3+%29