SOLUTION: solve {{{sqrt(y+4)+6=7}}} {{{3+sqrt(z-6)=sqrt(z+9)}}}

Algebra ->  Radicals -> SOLUTION: solve {{{sqrt(y+4)+6=7}}} {{{3+sqrt(z-6)=sqrt(z+9)}}}      Log On


   

Question 356975: solve
sqrt%28y%2B4%29%2B6=7
3%2Bsqrt%28z-6%29=sqrt%28z%2B9%29
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28y%2B4%29%2B6=7
sqrt%28y%2B4%29=1. Squaring both sides tyo eliminate the radical,
y%2B4=1,
y+=+-3. This value satisfies the original equation, so this is the final answer.
3%2Bsqrt%28z-6%29=sqrt%28z%2B9%29.
Squaring both sides, 9+%2B+6%2Asqrt%28z-6%29+%2Bz-6+=+z%2B9,
3%2B6%2Asqrt%28z-6%29+=+9,
6%2Asqrt%28z-6%29+=+6,
sqrt%28z-6%29+=+1,
z-6=1,
z=7. This value satisfies the original equation, so this is the final answer.