SOLUTION: sq root of 3x+7=3x+5

Algebra ->  Radicals -> SOLUTION: sq root of 3x+7=3x+5      Log On


   



Question 343483: sq root of 3x+7=3x+5
Found 2 solutions by Fombitz, solver91311:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%283x%2B7%29=3x%2B5
3x%2B7=9x%5E2%2B15x%2B15x%2B25
3x%2B7=9x%5E2%2B30x%2B25
9x%5E2%2B27x%2B18=0
x%5E2%2B3x%2B2=0
%28x%2B1%29%28x%2B2%29=0
Two solutions:
x%2B1=0
highlight%28x=-1%29
.
.
.
x%2B2=0
highlight%28x=-2%29

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


I presume that you want to solve this equation for , although you might have shown us a mocodium of courtesy by taking a scant few seconds to say so.



Square both sides:



Collect like terms on the left:



Divide by 9:



Solve the factorable quadratic for .

Check both roots to make sure you did not introduce an extraneous root in the process of squaring the equation in the first step.

John

My calculator said it, I believe it, that settles it