SOLUTION: The question is THE SQUARE ROOT of (128a^2b^4) DIVIDED BY THE SQUARE ROOT of (16ab). I know you have to multiply by the conjugate. After that, I get

Algebra ->  Radicals -> SOLUTION: The question is THE SQUARE ROOT of (128a^2b^4) DIVIDED BY THE SQUARE ROOT of (16ab). I know you have to multiply by the conjugate. After that, I get      Log On


   



Question 342906: The question is THE SQUARE ROOT of (128a^2b^4) DIVIDED BY
THE SQUARE ROOT of (16ab).
I know you have to multiply by the conjugate. After that, I get lost. Please help.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify first.
+sqrt%28128a%5E2b%5E4%29%2Fsqrt%2816ab%29=sqrt%28%28128a%5E2b%5E4%29%2F%2816ab%29%29
.
.
+sqrt%28128a%5E2b%5E4%29%2Fsqrt%2816ab%29=sqrt%288a%5E%282-1%29b%5E%284-1%29%29
.
.
+sqrt%28128a%5E2b%5E4%29%2Fsqrt%2816ab%29=sqrt%288ab%5E%283%29%29
.
.
+sqrt%28128a%5E2b%5E4%29%2Fsqrt%2816ab%29=sqrt%284b%5E2%2A2ab%29
.
.
+sqrt%28128a%5E2b%5E4%29%2Fsqrt%2816ab%29=sqrt%284b%5E2%29%2Asqrt%282ab%29
.
.
+sqrt%28128a%5E2b%5E4%29%2Fsqrt%2816ab%29=2b%2Asqrt%282ab%29