SOLUTION: triangle ABC has vertices at A(7,-4) B(-1,2) C(5,-6). determine whether the triangle has three, two, or no sides that are equal in length

Algebra ->  Radicals -> SOLUTION: triangle ABC has vertices at A(7,-4) B(-1,2) C(5,-6). determine whether the triangle has three, two, or no sides that are equal in length       Log On


   

Question 33467This question is from textbook
: triangle ABC has vertices at A(7,-4) B(-1,2) C(5,-6). determine whether the triangle has three, two, or no sides that are equal in length
d= distance fromula This question is from textbook

Answer by mukhopadhyay(490) About Me  (Show Source):
You can put this solution on YOUR website!
The vertices are at A(7,-4); B(-1,2); C(5,-6);
Length AB = Distance between (7,-4) and (-1,2) = Sqrt(64+36) = 10;
Length BC = Distance between (-1,2) and (5,-6) = Sqrt(64+36) = 10;
Length CA = Distance between (7,-4) and (5,-6) = Sqrt(4+4) = 2 sqrt(2);
Answer: The traingle has two equal sides.