SOLUTION: Simplify the radical expression: Square root of 108 divided by the square root of 2q to the 6th power I have been working on this for an hour...Please help!

Algebra ->  Radicals -> SOLUTION: Simplify the radical expression: Square root of 108 divided by the square root of 2q to the 6th power I have been working on this for an hour...Please help!      Log On


   

Question 333898: Simplify the radical expression:
Square root of 108 divided by the square root of 2q to the 6th power
I have been working on this for an hour...Please help!
Found 3 solutions by Alan3354, stanbon, jim_thompson5910:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Like this?
sqrt%28108%29%2Fsqrt%282q%5E6%29 ??
-----------------
= sqrt%28108%2F2q%5E6%29
= sqrt%2854%2Fq%5E6%29
= %28sqrt%289%2Fq%5E6%29%29%2A%28sqrt%286%29%29
= %283%2Fq%5E3%29%2Asqrt%286%29

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify the radical expression:
Square root of 108 divided by the square root of 2q to the 6th power
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Separate the perfect square factors from the others.
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= sqrt[36/q^6]*sqrt[3/2]
----
= (6/q^2)sqrt(3/2)
---
= (6/q^2)(sqrt(6)/2)
---
= (3/q^2)sqrt(6)
====================
Cheers,
Stan H.
====================

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!



So sqrt%28108%29%2Fsqrt%282q%5E6%29=%286%2Asqrt%283%29%29%2F%28q%5E3%2Asqrt%282%29%29


Now simplify %286%2Asqrt%283%29%29%2F%28q%5E3%2Asqrt%282%29%29 to get


So sqrt%28108%29%2Fsqrt%282q%5E6%29=%283%2Asqrt%286%29%29%2F%28q%5E3%29