SOLUTION: 1. Many people know that the weight of an object varies on different planets, but did you know that the weight of an object on Earth also varies according to the elevation of the o

Algebra ->  Radicals -> SOLUTION: 1. Many people know that the weight of an object varies on different planets, but did you know that the weight of an object on Earth also varies according to the elevation of the o      Log On


   



Question 333258: 1. Many people know that the weight of an object varies on different planets, but did you know that the weight of an object on Earth also varies according to the elevation of the object? In particular, the weight of an object follows this equation: w=Cr^-2, where C is a constant, w is the weight, and r is the distance that the object is from the center of Earth.
a. Solve the equation w=Cr^-2 for r.
b. Solve the equation w=Cr-2 for C.
c. Suppose that an object weighs 10 pounds when it is 100 miles from the center of the earth. Find the value of C? Show your work.
d. Use the value of C you found in 1c (above) to determine how much the object would weigh in Imaginary Village which is 200 miles from the center of the earth. Show your work. (3 points)

2. The equation gives the distance, D, in miles that a person can see to the horizon from a height, h, in miles.
a. Solve this equation for h.
b. Imaginary Mountain has an elevation of 9 miles. How far, to the nearest tenth of a mile, can you see to the horizon from the top of Imaginary Mountain? Explain how you arrived at this answer.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Both of these questions have been answered several times on this site, so you didn't follow the instructions that told you to look first before posting.

Then you didn't follow the instruction that said you must only ask one question per post.

Then you didn't follow the instruction that said to include a description of what you had tried.

You don't have a Mathematics problem. You have a reading, comprehending, and instruction following problem.

John

My calculator said it, I believe it, that settles it