SOLUTION: I have been having problems solving this problem. It says to solve with all extraneous solutions. Thank you for your time to help 5÷y-3 = y+7÷2y-6 +1

Algebra ->  Radicals -> SOLUTION: I have been having problems solving this problem. It says to solve with all extraneous solutions. Thank you for your time to help 5÷y-3 = y+7÷2y-6 +1      Log On


   

Question 330095: I have been having problems solving this problem. It says to solve with all extraneous solutions. Thank you for your time to help
5÷y-3 = y+7÷2y-6 +1
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
5%2F%28y-3%29+=+%28y%2B7%29%2F%282y-6%29++%2B1
5%2F%28y-3%29+=+%28%281%2F2%29%2A%28y%2B7%29%29%2F%28y-3%29++%2B%28y-3%29%2F%28y-3%29
5%2F%28y-3%29+=+%28%281%2F2%29%2A%28y%2B7%29%2B%28y-3%29%29%2F%28y-3%29
Multiply both sides by y-3.
5+=+%281%2F2%29%2A%28y%2B7%29%2B%28y-3%29
10+=+%28y%2B7%29%2B2%28y-3%29
y%2B7%2B2y-6=10
3y%2B1=10
3y=9
y=3
This solution is not allowed since the assumption was made that y did not equal 3 when multiplying both sides by y-3.
No solution.