

The square root radical
never indicates
a negative number. Therefore the right side of the above equation
cannot be negative. Therefore the left side, which begins with a
negative sign, could only have value 0. However that would make
be 0, which would give
. However, if we
substitute
in the right side we get
which
is undefined with real numbers.
So, there is no solution unless the - sign in front of the left
side was typo. If it was a typo, post again without the typo.
Edwin