SOLUTION: i^2 is then (-1)
1. what is i^3?
2. what is (i-1)(i+1)?
3. what is i^4?
4. What is i^n is n is an even number? and if n is an odd number?
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-> SOLUTION: i^2 is then (-1)
1. what is i^3?
2. what is (i-1)(i+1)?
3. what is i^4?
4. What is i^n is n is an even number? and if n is an odd number?
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Question 324178: i^2 is then (-1)
1. what is i^3?
2. what is (i-1)(i+1)?
3. what is i^4?
4. What is i^n is n is an even number? and if n is an odd number? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! i^2 is then (-1)
1. what is i^3?
= -i
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2. what is (i-1)(i+1)?
=
= -2
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3. what is i^4?
= 1
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4. What is i^n is n is an even number?
It's either -1 or +1.
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and if n is an odd number?
Either -i or +i
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Odd or even is not sufficient to specify the result. It's a modulo 4 function.
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i^n = i to the power of the remainder of n/4.
