SOLUTION: ~3/1+~2 * 1-~2/1-~2=
I have this
~3/1+~2*1
~3/1+~2*1-~2/1-~2
~3(1-~2)/(1)^2-(~2)^2
~3(1-~2)/1-(2)
-~3/1-(2)
-~3/1-2
-~3/-1
-(-~3/1)
~3
But the answer is suspose to be ~6
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Radicals
-> SOLUTION: ~3/1+~2 * 1-~2/1-~2=
I have this
~3/1+~2*1
~3/1+~2*1-~2/1-~2
~3(1-~2)/(1)^2-(~2)^2
~3(1-~2)/1-(2)
-~3/1-(2)
-~3/1-2
-~3/-1
-(-~3/1)
~3
But the answer is suspose to be ~6
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Question 322380: ~3/1+~2 * 1-~2/1-~2=
I have this
~3/1+~2*1
~3/1+~2*1-~2/1-~2
~3(1-~2)/(1)^2-(~2)^2
~3(1-~2)/1-(2)
-~3/1-(2)
-~3/1-2
-~3/-1
-(-~3/1)
~3
But the answer is suspose to be ~6-~3
So somewhere I messed up. Please help.
Thanks Answer by Fombitz(32388) (Show Source):
