SOLUTION: 1. y = 2sqrt(x + 3) by graphing 5 points. Use the endpoint of the function as your first point. y = 2 sqrt (x) + 3 x = 0, y = 2sqrt(0) + 3 = 3 x = 1, y = 2sqrt(

Algebra ->  Radicals -> SOLUTION: 1. y = 2sqrt(x + 3) by graphing 5 points. Use the endpoint of the function as your first point. y = 2 sqrt (x) + 3 x = 0, y = 2sqrt(0) + 3 = 3 x = 1, y = 2sqrt(      Log On


   

Question 316454: 1. y = 2sqrt(x + 3) by graphing 5 points. Use the endpoint of the function as your first point.
y = 2 sqrt (x) + 3
x = 0, y = 2sqrt(0) + 3 = 3
x = 1, y = 2sqrt(1) + 3 = 5
x = 9, y = 2sqrt(9) + 3 = 9
x = 16, y = 2sqrt(16) + 3 = 11
x = 25, y = 2sqrt(25) + 3 = 13
How do I find out what the endpoint is exactly ?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the graph "ends" at x=-3 because the square roots of negative values are not real numbers

your first point should be x=-3 and go up from there