SOLUTION: Please help me solve this equation {{{4+sqrt(10-x)=6+sqrt(4-x)}}}

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Question 296793: Please help me solve this equation
4%2Bsqrt%2810-x%29=6%2Bsqrt%284-x%29
Found 2 solutions by JBarnum, MathTherapy:
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
4%2Bsqrt%2810-x%29=6%2Bsqrt%284-x%29 square everything
4%5E2%2B%28sqrt%2810-x%29%29%5E2=6%5E2%2B%28sqrt%284-x%29%29%5E2
16%2B10-x=36%2B4-x
0=14 i come up with undefined, so there is no possible answer for x.

Answer by MathTherapy(10719) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me solve this equation
4%2Bsqrt%2810-x%29=6%2Bsqrt%284-x%29
******************************
This is UTTERLY CRAZY!! Who ever heard of this: 4%2Bsqrt%2810-x%29=6%2Bsqrt%284-x%29 square everything
4%5E2%2B%28sqrt%2810-x%29%29%5E2=6%5E2%2B%28sqrt%284-x%29%29%5E2 <=== Who in their right mind would square both sides of a square root problem like this? Why do
these people respond in this manner? This "HELP" is NO HELP at all!! Just leave the problem for someone who can handle it!
BTW, the person claimed this to be an UNDEFINED equation. In other words, there are no solutions! Really!! Ha-ha-ha! 

 4+%2B+sqrt%2810+-+x%29+=+6+%2B+sqrt%284+-+x%29
    sqrt%2810+-+x%29+=+2+%2B+sqrt%284+-+x%29
 %28sqrt%2810+-+x%29%29%5E2+=+%282+%2B+sqrt%284+-+x%29%29%5E2 --- Squaring BOTH sides, the CORRECT way
      10+-+x+=+4+%2B+4sqrt%284+-+x%29+%2B+4+-+x
10+-+8+-+x+%2B+x+=+4sqrt%284+-+x%29
         2+=+4sqrt%284+-+x%29
         1+=+2sqrt%284+-+x%29 ---- Dividing by GCF, 2
         1 = 4(4 - x) --- Squaring each side
         1 = 16 - 4x
    1 - 16 = - 4x
      - 15 = - 4x
    %28-+15%29%2F%28-+4%29+=+highlight%2815%2F4+=+x%29

This x-value, 15%2F4 is VALID!!