SOLUTION: Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five.

Algebra ->  Radicals -> SOLUTION: Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five.      Log On


   

Question 295475: Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five.
Answer by alicealc(293) About Me  (Show Source):
You can put this solution on YOUR website!
1st even number = x
2nd even number = x + 2
%281%2F2%29+%2A+%28x%2B2%29+-+%282%2F5%29+%2A+x+=+5
%281%2F2%29+%2A+%28x%2B2%29+-+%282%2F5%29+%2A+x+=+5
%281%2F2%29+%2A+x+%2B+%281%2F2%29+%2A+2+-+%282%2F5%29+%2A+x+=+5
%281%2F2%29+%2A+x+%2B+1+-+%282%2F5%29+%2A+x+=+5
%281%2F2%29+%2A+x+-+%282%2F5%29+%2A+x+=+5+-+1
1%2F2+%2A+x+-+2%2F5+%2A+x+=+4
5%2F10+%2A+x+-+4%2F10+%2A+x+=+4
1%2F10+%2A+x+=+4
x = 4 * 10/1
x = 40
1st even number = x = 40
2nd even number = x + 2 = 40 + 2 = 42

so the numbers will be 40 and 42