SOLUTION: 42. Find b^2 - 4ac and the number of real solutions to each equation. 14. Solve each equation by using the quadratic formula. -8q^2+2q+1=0

Algebra ->  Radicals -> SOLUTION: 42. Find b^2 - 4ac and the number of real solutions to each equation. 14. Solve each equation by using the quadratic formula. -8q^2+2q+1=0      Log On


   

Question 255674: 42. Find b^2 - 4ac and the number of real solutions to each equation.
14. Solve each equation by using the quadratic formula. -8q^2+2q+1=0
Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
-8q%5E2%2B2q%2B1=0
a=-8
b=2
c=1
So, b%5E2-4ac is:
2%5E2-4%28-8%29%281%29+=+4%2B32+=+36%0D%0A%0D%0ANow%2C+since+%7B%7B%7Bb%5E2-4ac+%3E+0 we know that the formula has 2 real solutions.