SOLUTION: how do you simplify the 8th root of 16x^4 y^12

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Question 249706: how do you simplify the 8th root of 16x^4 y^12
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
the 8th root of 16x%5E4%2Ay%5E12

First we need to know what this means. "the 8th root of 16x%5E4%2Ay%5E12 means root%288%2C+16x%5E4%2Ay%5E12%29
Second, it helps if we understand how to write this using fractional exponents.
root%288%2C+16x%5E4%2Ay%5E12%29+=+%2816x%5E4%2Ay%5E12%29%5E%281%2F8%29
Next, we should recognize that 16x%5E4%2Ay%5E12%29 is a single term (with many factors). Since it is a single term, the following rule for exponents applies:
%28a%2Ab%2Ac%29%5Ed+=+a%5Ed%2Ab%5Ed%2Ac%5Ed
(This looks similar to the Distributive Property but it is not the Distributive Property.) We can use this to raise each factor to the 1/8th power:

Since 16+=+2%5E4 we can rewrite this as:
%282%5E4%29%5E%281%2F8%29%2A%28x%5E4%29%5E%281%2F8%29%2A%28y%5E12%29%5E%281%2F8%29
Now we can use another rule for exponents, %28a%5Ep%29%5Eq+=+a%5E%28p%2Aq%29, to simplify the expression:
2%5E%284%2A%281%2F8%29%29%2Ax%5E%284%2A%281%2F8%29%29%2Ay%5E%2812%2A%281%2F8%29%29
which simplifies to:
2%5E%281%2F2%29%2Ax%5E%281%2F2%29%2Ay%5E%283%2F2%29
(Can you now see why we changed 16 into 2%5E4?)
Since all the exponents have the same denominator they all represent the same root: square root. We can factor out a 1/2 from each exponent using the earlier property (in the other direction):
%282xy%5E3%29%5E%281%2F2%29
To finish this we will write it will a radical:
sqrt%282xy%5E3%29
The only thing left here is to simplify, if possible. Simplifying square roots involves finding perfect square factors, if any. We do have a perfect square factor, y%5E2, which we can factor out:

(Note that we can't say sqrt%28y%5E2%29+=+y because square roots are positive but y does not have to be positive. So we use abs%28y%29 to ensure that we end up with a positive number.)