SOLUTION: We're rationalizing the demoninator. I'm having difficulty solving this: 4 ----- The Cube root of 3. Help?

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Question 22803: We're rationalizing the demoninator. I'm having difficulty solving this:
4
-----
The Cube root of 3.
Help?
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Before beginning ANY cube root problem, be sure that you know your perfect cubes. That is,
2%5E3=8, 3%5E3=+27, 4%5E3=+64, 5%5E3=125

Now, 4%2F+root%283%2C3%29

The idea is to somehow get the number in that radical in the denominator up to a perfect cube. When you think of the 3 inside the cube root sign, what perfect cube comes to mind associated with 3? The answer should be 27.

You need to get that denominator from 3 up to 27, by multiplying it by 9. In other words you must multiply the numerator and denominator by the cube root of 9.
%284%2F+root%283%2C3%29+%29%2A%28%28root%283%2C9%29%29%2F%28root%283%2C9%29%29%29
Multiply numerator times numerator and denominator times denominator:
= %284%2A+root%283%2C9%29+%29%2F%28root%283%2C27%29%29%29= %284%2A+root+%283%2C9%29%29%2F3= %284%2F3%29%2A+root%283%2C9%29

R^2 at SCC