SOLUTION: I need to find the value of tan(theta) but the only value I have is sin(theta)=1/4 and it is in quadrant I.
I know that (sin)(sin)theta + (cos)(cos)theta=1 so if sin(theta)= 1/
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-> SOLUTION: I need to find the value of tan(theta) but the only value I have is sin(theta)=1/4 and it is in quadrant I.
I know that (sin)(sin)theta + (cos)(cos)theta=1 so if sin(theta)= 1/
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Question 211542: I need to find the value of tan(theta) but the only value I have is sin(theta)=1/4 and it is in quadrant I.
I know that (sin)(sin)theta + (cos)(cos)theta=1 so if sin(theta)= 1/4 then sin(sin)theta =1/16... so cos(cos)theta=square root of 15/16.. and this is positive because the values are in quadrant I which is always positive. From there I know that sin(theta) over cos(theta) will give me tan(theta) but I dont know how to simplify from there. Can you help me with that? Answer by jim_thompson5910(35256) (Show Source):
... Take the square root of both sides. Note: because is in the first quadrant, this means that (ie cosine is positive). So we don't need to worry about the negative square root.
... Break up the square root.
... Take the square root of 16 to get 4.
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... Move onto the tangent identity.
... Plug in and
... Multiply the first fraction by the reciprocal of the second fraction.
... Cancel out the common terms and simplify.
... Multiply the fraction by (this will rationalize the denominator).