SOLUTION: Please walk me through each step in solving this problem: Square root of 25x - 25 minus square root of 9x-9. (Sorry, I cannot product the square root symbol). They say the ans

Algebra ->  Radicals -> SOLUTION: Please walk me through each step in solving this problem: Square root of 25x - 25 minus square root of 9x-9. (Sorry, I cannot product the square root symbol). They say the ans      Log On


   

Question 200827: Please walk me through each step in solving this problem:
Square root of 25x - 25 minus square root of 9x-9. (Sorry, I cannot product the square root symbol). They say the answer is 2times square root of x-1
Found 2 solutions by jim_thompson5910, checkley77:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%2825x-25%29-sqrt%289x-9%29 Start with the given expression.


sqrt%2825%28x-1%29%29-sqrt%289x-9%29 Factor out the GCF 25 from the first radicand


sqrt%2825%28x-1%29%29-sqrt%289%28x-1%29%29 Factor out the GCF 9 from the second radicand


sqrt%2825%29%2Asqrt%28x-1%29-sqrt%289%29%2Asqrt%28x-1%29 Break up the roots using the identity sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29


5%2Asqrt%28x-1%29-sqrt%289%29%2Asqrt%28x-1%29 Take the square root of 25 to get 5


5%2Asqrt%28x-1%29-3%2Asqrt%28x-1%29 Take the square root of 9 to get 3


%285-3%29%2Asqrt%28x-1%29 Factor out the GCF sqrt%28x-1%29


2%2Asqrt%28x-1%29 Combine like terms.



So sqrt%2825x-25%29-sqrt%289x-9%29=2%2Asqrt%28x-1%29 where x%3E=1

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt(25x-25)-sqrt(9x-9)
sqrt25(x-1)-sqrt9(x-1)
5sqrt(x-1)-3sqrt(x-1)
5-3sqrt(x-1)
2sqrt(x-1)