SOLUTION: 5x squared + 2x - 3 = 0 I added 3 on both sides. 5x squared + 2x = 3 But i'm a bit lost. Someone please help me. I'd provide you with a book but we don't use books in my ma

Algebra ->  Radicals -> SOLUTION: 5x squared + 2x - 3 = 0 I added 3 on both sides. 5x squared + 2x = 3 But i'm a bit lost. Someone please help me. I'd provide you with a book but we don't use books in my ma      Log On


   

Question 194496: 5x squared + 2x - 3 = 0
I added 3 on both sides.
5x squared + 2x = 3
But i'm a bit lost.
Someone please help me. I'd provide you with a book but we don't use books in my math class.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

5x%5E2%2B2x-3=0 Start with the given equation.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=5, b=2, and c=-3


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%282%29+%2B-+sqrt%28+%282%29%5E2-4%285%29%28-3%29+%29%29%2F%282%285%29%29 Plug in a=5, b=2, and c=-3


x+=+%28-2+%2B-+sqrt%28+4-4%285%29%28-3%29+%29%29%2F%282%285%29%29 Square 2 to get 4.


x+=+%28-2+%2B-+sqrt%28+4--60+%29%29%2F%282%285%29%29 Multiply 4%285%29%28-3%29 to get -60


x+=+%28-2+%2B-+sqrt%28+4%2B60+%29%29%2F%282%285%29%29 Rewrite sqrt%284--60%29 as sqrt%284%2B60%29


x+=+%28-2+%2B-+sqrt%28+64+%29%29%2F%282%285%29%29 Add 4 to 60 to get 64


x+=+%28-2+%2B-+sqrt%28+64+%29%29%2F%2810%29 Multiply 2 and 5 to get 10.


x+=+%28-2+%2B-+8%29%2F%2810%29 Take the square root of 64 to get 8.


x+=+%28-2+%2B+8%29%2F%2810%29 or x+=+%28-2+-+8%29%2F%2810%29 Break up the expression.


x+=+%286%29%2F%2810%29 or x+=++%28-10%29%2F%2810%29 Combine like terms.


x+=+3%2F5 or x+=+-1 Simplify.


So the answers are x+=+3%2F5 or x+=+-1