SOLUTION: 3x^2+1=2x is the problem Which ever side i place the equation on i end up with a negative as a square root and i remember my professor mentioning you cant have a negative square

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Question 193314: 3x^2+1=2x is the problem
Which ever side i place the equation on i end up with a negative as a square root and i remember my professor mentioning you cant have a negative square root. I end up with X= -2+/- the sq. root of -8 over 6
What is my problem here?

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
3x%5E2%2B1+=+2x First subtract 2x from both sides of the equation.
3x%5E2-2x%2B1+=+0 Solve this quadratic equation using the quadratic formula: x+=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a
In this problem, a = 3, b = -2, and c = 1. Make the appropriate substitutions;
x+=+%28-%28-2%29%2B-sqrt%28%28-2%29%5E2-4%283%29%281%29%29%29%2F2%283%29
x+=+%282%2B-sqrt%284-12%29%29%2F6
x+=+%282%2B-sqrt%28-8%29%29%2F6
x+=+%282%2B-sqrt%284%2A%28-2%29%29%29%2F6
highlight%28x+%2B+%281%2Bsqrt%28-2%29%29%2F3%29 or highlight%28x+=+%281-sqrt%28-2%29%29%2F3%29
Perhaps you misunderstood your professor. Negative square roots occur a lot in math. If I were you, I would ask him/her to clarify the statement.