SOLUTION: I am using the "Glenco mathmatics Algebra 1" book. I am doing extra practice in the back of the book in section 11-1. #24. The problem is using the process of simplifying radical e

Algebra ->  Radicals -> SOLUTION: I am using the "Glenco mathmatics Algebra 1" book. I am doing extra practice in the back of the book in section 11-1. #24. The problem is using the process of simplifying radical e      Log On


   

Question 191991This question is from textbook Algebra I
: I am using the "Glenco mathmatics Algebra 1" book. I am doing extra practice in the back of the book in section 11-1. #24. The problem is using the process of simplifying radical expressions. square+root+of+27p%5E4%2F3p%5E2 This question is from textbook Algebra I

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28%2827p%5E4%29%2F%283p%5E2%29%29 Start with the given expression.


sqrt%289p%5E2%29 Divide %2827p%5E4%29%2F%283p%5E2%29 to get 9p%5E2


sqrt%289%29%2Asqrt%28p%5E2%29 Break up the square root using the identity sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29.


3%2Asqrt%28p%5E2%29 Take the square root of 9 to get 3.


3p Take the square root of p%5E2 to get p.


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Answer:


So sqrt%289%2Ap%5E2%29 simplifies to 3p


In other words, sqrt%289%2Ap%5E2%29=3p where p%3E=0.