SOLUTION: Solve the equation. -5^3square root x-2=15 I worked it out to: ^3square root x-2=3 (^3square root x-2)^3=(-3)^3 x-2=-27 x=-25 Am I correct?

Algebra ->  Radicals -> SOLUTION: Solve the equation. -5^3square root x-2=15 I worked it out to: ^3square root x-2=3 (^3square root x-2)^3=(-3)^3 x-2=-27 x=-25 Am I correct?       Log On


   

Question 190471This question is from textbook saxon algebra 2
: Solve the equation.
-5^3square root x-2=15
I worked it out to:
^3square root x-2=3
(^3square root x-2)^3=(-3)^3
x-2=-27
x=-25
Am I correct?
 This question is from textbook saxon algebra 2

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!

To the extent that you meant



Yes.

Next time you need to express a radical with an index, do it this way:

root(n,x) which would mean -- yours here would have been

-5*root(3, x - 2)=15

John