SOLUTION: {{{3sqrt(-64)}}}+{{{sqrt(9)}}}[ {{{1/3}}}{{{(-3^2-5)9-(-1)^5}}} ] I have no idea how to solve this. I tried to type it the best I could. Please help if you can. Note: For the fi

Algebra ->  Radicals -> SOLUTION: {{{3sqrt(-64)}}}+{{{sqrt(9)}}}[ {{{1/3}}}{{{(-3^2-5)9-(-1)^5}}} ] I have no idea how to solve this. I tried to type it the best I could. Please help if you can. Note: For the fi      Log On


   

Question 189214: 3sqrt%28-64%29+sqrt%289%29[ 1%2F3%28-3%5E2-5%299-%28-1%29%5E5 ]
I have no idea how to solve this. I tried to type it the best I could. Please help if you can. Note: For the first part the 3 is the index and the -64 is the radicand.
Thank you ^_^
Found 2 solutions by Mathtut, Alan3354:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
root%283%2C-64%29=4i
:
which is to be added to multiplied by 3* (1/3)(-9-5)*9+1=1*(-14*10)=-140
:
so we have 4i-140

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
3sqrt%28-64%29+sqrt%289%29[ 1%2F3%28-3%5E2-5%299-%28-1%29%5E5 ]
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You can't solve it, it's not an equation. It can be simplified is all.
The cube root of -64 is -4, so:
= -4 + 3*((1/3)*(-3^2-5)*9 - (-1)^5)
= -4 + 3*((1/3)*(-14)*9 + 1)
= -4 + 3*(-42 + 1)
= -4 + 3*(-41)
= -4 - 123
= -127