SOLUTION: I cannot solve the following, please help and show step by step if possible, thank you using the quadratic formula -8q^2-2q+1=0

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Question 176655This question is from textbook Elementary and Intermediate Algebra
: I cannot solve the following, please help and show step by step if possible, thank you
using the quadratic formula
-8q^2-2q+1=0 This question is from textbook Elementary and Intermediate Algebra

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
-8q%5E2-2q%2B1=0
8q%5E2%2B2q-1=0
Using the quadratic formula,
q=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
q+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A8%2A%28-1%29+%29%29%2F%282%2A8%29+
q+=+%28-2+%2B-+sqrt%28+4%2B32%29%29%2F%2816%29+
q+=+%28-2+%2B-+sqrt%28+36%29%29%2F%2816%29+
q+=+%28-2+%2B-+6%29%2F%2816%29+
First solution:
q+=+%28-2+%2B+6%29%2F%2816%29+
q+=+%284%29%2F%2816%29+
q=1%2F4
Second solution:
q+=+%28-2+-+6%29%2F%2816%29+
q+=+%28-8%29%2F%2816%29+
q+=+-1%2F2+
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You can factor this quadratic,
%284q-1%29%282q%2B1%29=0
First solution:
4q-1=0
4q=1
q=1%2F4
Second solution:
2q%2B1=0
2q=-1
q=-1%2F2
Here's a graph of the function to verify the zeros.
+graph%28+300%2C+300%2C+-3%2C+3%2C+-3%2C+3%2C+8x%5E2%2B2x-1%29+