SOLUTION: Simplify [√32x^5y^2] / [√2x^3y^3] Thank you.

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Question 176298: Simplify [√32x^5y^2] / [√2x^3y^3] Thank you.
Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
First of all, I have to assume this is what you mean:
%28sqrt%2832%29x%5E5y%5E2%29%2F%28sqrt%282%29x%5E3y%5E3%29
First, let's deal with sqrt(32). Note that since 32=16*2, we can write it as
sqrt%2832%29=sqrt%2816%2A2%29=sqrt%2816%29sqrt%282%29=4sqrt%282%29
So we have
%284sqrt%282%29x%5E5y%5E2%29%2F%28sqrt%282%29x%5E3y%5E3%29
Now, the sqrt(2) will cancel out, leaving:
%284x%5E5y%5E2%29%2F%28x%5E3y%5E3%29
Now, there is x^5 on top and x^3 on bottom. You can look at this two ways: if you were to write them out, you'd have xxxxx/xxx. Three of the x's would cancel, leaving two on top, or x^2. The rule is, when you have division, you subtract the exponents. So x^5/x^3=x^(5-3)=x^2. Similarly, with the y's we are left with one on the bottom. So simplified we have:
%284x%5E2%29%2Fy