SOLUTION: Can you please help me find the solution for {{{x^2+20x}}} your help is greatly appreciated.

Algebra ->  Radicals -> SOLUTION: Can you please help me find the solution for {{{x^2+20x}}} your help is greatly appreciated.      Log On


   

Question 173959This question is from textbook algebra 1 concepts and skill
: Can you please help me find the solution for x%5E2%2B20x
your help is greatly appreciated. This question is from textbook algebra 1 concepts and skill

Found 2 solutions by Mathtut, Electrified_Levi:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
this is only and expression....do you have and equation(has an equals sign)
:
such as y=x%5E2%2B20x or x%5E2%2B20x=0
if your factoring an expression:
:
this would be
:
x%28x%2B20%29

Answer by Electrified_Levi(103) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, Hope I can help,
.
Can you please help me find the solution for x%5E2%2B20x
your help is greatly appreciated.
.
I believe this is the equation, x%5E2%2B20x+=+0+
.
For this equation, we can just factor this polynomial, and find the solutions
.
We can factor out an "x"
.
x%5E2%2B20x+=+0+ = +x%28x%2B20%29+=+0+
.
There are two solutions, so we have two equations, we have to let both of the factors equal "0", then solve for "x"
.
(x), +x+=+0+, +x+=+0+ is our first answer
.
(x+20), +x%2B20+=+0+ = +x+%2B+20+-+20+=+0+-+20+ = +x+=+-20+, this is our second answer
.
+x+=+0+ and +x+=+-20+, are your two solutions
.
You can always use the quadratic equation
.
x%5E2%2B20x+=+0+, you can also say x%5E2%2B20x+%2B+0+=+0+
.
x%5E2%2B20x+%2B+0+=+0+, quadratic equations are given in the form ax%5E2%2Bbx+%2B+c+=+0+
.
Quadratic equation = x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
.
x%5E2%2B20x+%2B+0+=+0+, ax%5E2%2Bbx+%2B+c+=+0+
.
Our equation
.
a = 1
.
b = 20
.
c = 0
.
Now just replace the letters with the numbers
.
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ = x+=+%28-%2820%29+%2B-+sqrt%28+%2820%29%5E2-4%2A%281%29%2A%280%29+%29%29%2F%282%2A%281%29%29+ = x+=+%28-20+%2B-+sqrt%28+400-0+%29%29%2F2+ = x+=+%28-20+%2B-+sqrt%28+400%29%29%2F2+ = x+=+%28-20+%2B-+20%29%2F2+
.
x+=+%28-20+%2B+20%29%2F2+ = x+=+0%2F2+ = +x+=+0+
.
x+=+%28-20+-+20%29%2F2+ = +x+=+%28-40%29%2F2+ = +x+=+-20+
.
+x+=+0+ and +x+=+-20+ are your two solutions
.
Hope I helped, Levi