SOLUTION: Graph the quadratic equation and label the ordered pairs for the vertex and the y-intercept. y = x^2 + x - 2

Algebra ->  Radicals -> SOLUTION: Graph the quadratic equation and label the ordered pairs for the vertex and the y-intercept. y = x^2 + x - 2      Log On


   

Question 172483This question is from textbook Introductory Algebra
: Graph the quadratic equation and label the ordered pairs for the vertex and the y-intercept.
y = x^2 + x - 2 This question is from textbook Introductory Algebra

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
A function written in the form ---> f%28x%29=a%28x-h%29%5E2%2Bk, where (h,k) the vertex.
Given: f%28x%29=x%5E2%2Bx-2, we complete the square:
f%28x%29=%28x%5E2%2Bx%2B1%2F4%29highlight%28-1%2F4%29-2, Add 1%2F4, and also subtract 1%2F4 so the expression won't change.
*Note: How we get 1%2F4? Take half of the middle term constant (which in this case is "1") then squared it. ---> %281%2F2%29%5E2=1%2F4
Continuing;
f%28x%29=%28x%2B1%2F2%29%5E2-2.25 ----> highlight%28h=-1%2F2%29, highlight%28k=-2.25%29
For the Y-Intercept:
f%28x%29=0
f%280%29=0%5E2%2B0-2
Therefore: Y-Intercept is highlight%28-2%29
let's see the graph:

Thank you,
Jojo