SOLUTION: Please assist me in finding the solution to this problem... I've tried I am not sure if I am doing it correctly. Thanks a^(2/5)b^(1/3)

Algebra ->  Radicals -> SOLUTION: Please assist me in finding the solution to this problem... I've tried I am not sure if I am doing it correctly. Thanks a^(2/5)b^(1/3)       Log On


   

Question 169282: Please assist me in finding the solution to this problem... I've tried I am not sure if I am doing it correctly. Thanks
a^(2/5)b^(1/3)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Please assist me in finding the solution to this problem... I've tried I am not sure if I am doing it correctly. Thanks
a^(2/5)b^(1/3)
--------------
It's not a problem to be solved, just an expression.
It can be "simplified", tho that's sometimes a matter of opinion as to what is simpler.
-------------
a^(2/5)b^(1/3)
Get the a and b terms to the same exponent: 1/5 x 1/3 = 1/15
a^(2/5)b^(1/3)
=%28a%5E6%29%5E%281%2F15%29%2A%28b%5E5%29%5E%281%2F15%29 See that?
=%28a%5E6b%5E5%29%5E%281%2F15%29
It's simplified in the sense that there's only one fractional exponent, or root.