SOLUTION: How will I go about simplifing these problem? 1) 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)] 2) 3/[SQRT(5) - 2] And how can I solve this problem? 3) {{{SQRT(x + 4) = SQRT(x)

Algebra ->  Radicals -> SOLUTION: How will I go about simplifing these problem? 1) 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)] 2) 3/[SQRT(5) - 2] And how can I solve this problem? 3) {{{SQRT(x + 4) = SQRT(x)       Log On


   

Question 162768: How will I go about simplifing these problem?
1) 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
2) 3/[SQRT(5) - 2]
And how can I solve this problem?
3) SQRT%28x+%2B+4%29+=+SQRT%28x%29+-+2
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
1)
3b(27a^5b)^(1/2)+2a(3a^3b^3)^(1/2)
3b((3*9)a^5b)^1/2+...
9b(sqrt(3)a^2.5b^.5)+...
9sqrt(3)a^2.5b^1.5...
...2a(sqrt(3)a^1.5b^1.5)
...2sqrt(3)a^2.5b^1.5
=11sqrt(3)a^2.5b^1.5
.
2)
3/(sqrt(5)-2)
=%283%2F%28sqrt%285%29-2%29%29%2A+%28%28sqrt%285%29%2B2%29%2F%28sqrt%285%29%2B2%29%29
=(3sqrt(5)+6)/(5-4)
=3sqrt(5)+6
.
3)
SQRT%28x+%2B+4%29+=+SQRT%28x%29+-+2
x+4=x-4sqrt(x)+4 Square each side.
-4sqrt(x)=0
16x=0 square each side
x=0
replace x with zero in the equation. It is not an equation. There is no answer.
.
Ed