Question 157288This question is from textbook elementary and intermediate algebra
: How do I find the discriminant? The question ask to find and the number of real solutions to each equation.
35. 
45.
This question is from textbook elementary and intermediate algebra
Found 2 solutions by Edwin McCravy, SAT Math Tutor: Answer by Edwin McCravy(20054) (Show Source):
You can put this solution on YOUR website! How do I find the discriminant? The question ask to find and the number of real solutions to each equation.
35. 
45.
You must first rearrange the equations so that 0 appears
on the right and the three terms on the left are in
descending order like this:
, or whatever
the letter of the unknown happens to be:
That's the only way you can tell what to substitute for
, , and in the formula:
-------
For your problem 35:
You must first get a 0 on the right side by adding to
both sides:
And you must write the left side in descending order, like
this:
Then when you compare that to
,
it is easy to see that , , and .
So then you can easily substitute those values in the
expression for the discriminant:
When the discriminant is 0, there is
exactly 1 real solution. So this particular
quadratic equation has 1 real solution.
If it were negative there would be no real solutions,
and if it were positive there would be exactly two real
solutions.
---------------------------------
For your problem 45:
You must first get a 0 on the right side by adding to
both sides:
But the left side contains only two terms! So you must
add on a to the left side:
Also it may be helpful to write the understood 's before
and , like this:
The left side is already in descending order, so when you
compare that to
,
it is easy to see that , , and .
So then you can easily substitute those values in the
expression for the discriminant:
Since the discriminant is a positive number,
there are exactly two real solutions.
Edwin
Answer by SAT Math Tutor(36) (Show Source):
You can put this solution on YOUR website! Begin by setting up a quadratic equation equal to zero so:
35. 4m^2 - 20m + 25 = 0
45. x^2 - x = 0
Then, label a, b, and c which are the coefficients:
35. a = 4, b = -20, c = 25
45. a = 1, b = -1, c = 0
Then, use the discriminant formula b^2 - 4ac:
35. (-20)^2 - 4(4)(25) = 0
45. 1^2 - 4(1)(0) = 1
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