SOLUTION: Can someone please help me. If y=cuberoot(x)-1 fill in the following table for x=0,1,2,3,4. Round to three deccimal places where necessary, explain why no negative values are chose

Algebra ->  Radicals -> SOLUTION: Can someone please help me. If y=cuberoot(x)-1 fill in the following table for x=0,1,2,3,4. Round to three deccimal places where necessary, explain why no negative values are chose      Log On


   

Question 151194This question is from textbook
: Can someone please help me. If y=cuberoot(x)-1 fill in the following table for x=0,1,2,3,4. Round to three deccimal places where necessary, explain why no negative values are chosen as values to substitute in for x. Thank you This question is from textbook

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
I would just use a calculator to find the cuberoot of 0, 1 ,2,3 and 4. Then round to three decimals and subtract 1
There is no reason why no negatives are there. negatives square roots result in imaginary numbers. But negative cuberoots exist (for instance cuberoot of -8 is -2). However many tools cannot plot them well. See the plot below. The negative roots are a mirror image, but they don't show

graph%28400%2C400%2C+-10%2C10%2C-10%2C10%2C+x%5E%281%2F3%29+-1%29