SOLUTION: When I use the formula T^2/R^3 (Kepler's third law). The only variable given in the problem is the variable for R (which is 0.723 Astronomical Units). When I replace the R with t

Algebra ->  Radicals -> SOLUTION: When I use the formula T^2/R^3 (Kepler's third law). The only variable given in the problem is the variable for R (which is 0.723 Astronomical Units). When I replace the R with t      Log On


   



Question 144805: When I use the formula T^2/R^3 (Kepler's third law). The only variable given in the problem is the variable for R (which is 0.723 Astronomical Units). When I replace the R with that factor. How can I solve the equation. I tried setting it equal to 0 but that is going to make the answer 0. In case you cannot find the problem, I am indicating it here:
#108) If the average radius of the orbit of Venus is 0.723 AU, then how many years does it take for Venuis to complete one orbit of the sun? Use the information in Exercise 107
FOR REFERENCE #107)Kepler's third law.
According to Kepler's third law of planetary motion, the ration T^2/R^3 has the same value for every planet in our solar system. R is the average radius of the orbit of the planet measured in astronomical units (AU), and T is the number of years it takes for one complete orbit of the sun.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
Kepler's Third Law:
T%5E2%2FR%5E3
Given:
R+=0.723 Astronomical Units
T%5E2%2FR%5E3=1………1 stands for one complete orbit of the sun
T%5E2=+%280.723+%29%5E3
T%5E2=+0.377933067
T=+sqrt%280.377933067%29
T=0.61476261028139959578935214317083 Earth years
……………which is 0.61476261028139959578935214317083%2A365=224.38835275271085246311353225705 Earth days
Or approximately
T=0.615 Earth years……………which is 0.615%2A365=224.475 Earth days