SOLUTION: Studying for final tomorrow having trouble understanding how to simplify radical equations. Need help fast please. example:6√7 - 2 √28 and √32 ∙ &#

Algebra ->  Radicals -> SOLUTION: Studying for final tomorrow having trouble understanding how to simplify radical equations. Need help fast please. example:6√7 - 2 √28 and √32 ∙ &#      Log On


   

Question 142722This question is from textbook Prentice Hall Mathmatics
: Studying for final tomorrow having trouble understanding how to simplify radical equations. Need help fast please.
example:6√7 - 2 √28
and
√32 ∙ √144 This question is from textbook Prentice Hall Mathmatics

Found 2 solutions by Edwin McCravy, stanbon:
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
example:


6sqrt%287%29-2sqrt%2828%29
Change 28 to 4%2A7
6sqrt%287%29-2sqrt%284%2A7%29
6sqrt%287%29-2sqrt%284%29sqrt%287%29
6sqrt%287%29-2%282%29sqrt%287%29
6sqrt%287%29-4sqrt%287%29
2sqrt%287%29
and
sqrt%2832%29%2Asqrt%28144%29
Write 32 as 16%2A2
and write 144 as 12%5E2
sqrt%2816%2A2%29%2Asqrt%2812%5E2%29
sqrt%2816%29sqrt%282%29%2A12
4sqrt%282%29%2A12
48sqrt%282%29
Edwin

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
example:
6√7 - 2 √28
= 6*sqrt(7) - 2*sqrt(4*7)
= 6*sqrt(7) - 2*2*sqrt(7)
= 6*sqrt(7) - 4*sqrt(7)
= 2*sqrt(7)
============================
and
√32 ∙ √144
= sqrt(16*2) * sqrt(144)
= 4*sqrt(2) *12
= 48*sqrt(2)
================
Cheers,
Stan H.