SOLUTION: please help me with this{{{cubert of 32y^7 - 3cubert 108y11}}}
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Algebra: Radicals -- complicated equations involving roots
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Question 140650
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please help me with this
Answer by
checkley77(12844)
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cubert 32y^7 - 3cubert 108y11
cubert (8*4*y^6*y) -3cubert (27*4*y^9*y^2)
2y^2cubert (4y)-3*3y^3cubert (4y^2)
2y^2cubert (4y)-9y^3cubert (4y^2) answer.