SOLUTION: hi,could you please help me solve this equation?
f(x)=(3x^5/2) Y^5/2 √25x^4y^4
I attempted to simplify the last part of the equation to 5x^2y^2, but then i got lost when i
Algebra ->
Radicals
-> SOLUTION: hi,could you please help me solve this equation?
f(x)=(3x^5/2) Y^5/2 √25x^4y^4
I attempted to simplify the last part of the equation to 5x^2y^2, but then i got lost when i
Log On
Question 139988: hi,could you please help me solve this equation?
f(x)=(3x^5/2) Y^5/2 √25x^4y^4
I attempted to simplify the last part of the equation to 5x^2y^2, but then i got lost when i tried to simplify the whole thing together. thanks for your help in advance. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! f(x)=(3x^5/2) Y^5/2 √25x^4y^4
f(x) = 3x^(5/2) * y^(5/2) * 5x^2 y^2
f(x) = 15*x^(9/2) y^(9/2)
========================
Cheers,
Stan H.
(