SOLUTION: Determine the type of number(s) that the solutions of x^2-2x+5=0 will be: a) one real b) two real c) two non-real d) no solution

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Question 136722: Determine the type of number(s) that the solutions of x^2-2x+5=0 will be:
a) one real
b) two real
c) two non-real
d) no solution
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ is the quadratic formula. The part under the radical, b%5E2-4ac is called the discriminant.

If b%5E2-4ac%3E0, then you have two real and unequal roots.

If b%5E2-4ac=0, then you have two real and equal roots. Also described as one real root with a multiplicity of 2.

If b%5E2-4ac%3C0, then you have a conjugate pair of complex roots of the form a%2B-bi where i is the imaginary number defined as i%5E2=-1.