SOLUTION: Please help, it says to solve by completing the square. x^2-3x+1=0 What I got for this was x-2 x+8 2-83 I am not so sure about my answer, please help! Thank You=)

Algebra ->  Radicals -> SOLUTION: Please help, it says to solve by completing the square. x^2-3x+1=0 What I got for this was x-2 x+8 2-83 I am not so sure about my answer, please help! Thank You=)      Log On


   

Question 136353: Please help, it says to solve by completing the square.
x^2-3x+1=0
What I got for this was x-2 x+8 2-83
I am not so sure about my answer, please help! Thank You=)
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Given: x%5E2-3x%2B1=0
to complete the square, use this format
(ax^2 + 2abx + b^2)
We are given
x%5E2-3x%2B1=0 , so a = 1 and 2ab=-3 --> b = -3/2 --> b^2 = 9/4

x%5E2-3x+%2B+9%2F4++%2B1=+%289%2F4%29 whatever you do to one side, you need to do to the other
%28x-+1.5%29%5E2+=+%289%2F4%29+-+1+
+%28x-1.5%29%5E2+=+5%2F4+
+%28x-1.5%29+=+sqrt%285%2F4%29
x+=+sqrt%285%2F4%29+%2B+1.5+
x+=+1.5+%2B+sqrt%285%29%2F2
x+=+1.5+-+sqrt%285%29%2F2