SOLUTION: Rationalize the denominator: 8 - radical 2 divided by 6 - 3 square root 2

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Question 135224: Rationalize the denominator:
8 - radical 2 divided by 6 - 3 square root 2

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
%288-sqrt%282%29%29%2F%286-3sqrt%282%29%29

The trick is to multiply the fraction by 1 in the form of the conjugate of the denominator divided by itself.

If you have an expression of the form a%2Bb%2Asqrt%28c%29, then its conjugate is a-b%2Asqrt%28c%29, and vice versa of course.

Here your denominator expression is 6-3sqrt%282%29, so the conjugate is 6%2B3sqrt%282%29, so you need to multiply your original fraction by 1 in the form of %286%2B3sqrt%282%29%29%2F%286%2B3sqrt%282%29%29



Notice that multiplying a binomial times its conjugate is the reverse of factoring the difference of two squares -- so the result is the first term squared minus the second term squared. Just use FOIL on the numerator expressions:



The result is a fraction with a rational number in the denominator, hence the name of the process.