SOLUTION: Hi, If someone could please help me that would be great. I need to rationalize the denominator. It is a number 1 in the (numerator)over top of a square root of 7 minus a square roo
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-> SOLUTION: Hi, If someone could please help me that would be great. I need to rationalize the denominator. It is a number 1 in the (numerator)over top of a square root of 7 minus a square roo
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Question 133239This question is from textbook Beginning and Intermediate Algebra
: Hi, If someone could please help me that would be great. I need to rationalize the denominator. It is a number 1 in the (numerator)over top of a square root of 7 minus a square root of 5 in the denominator. I came up with the answer of a square root of 7 + a square root of 5 in the numerator over top of a 2 in the denominator. Is this right. I couldn't figure out how to write out this problem on the computer.
Thanks, Randy This question is from textbook Beginning and Intermediate Algebra
You can put this solution on YOUR website! rationalize the denominator. It is a number 1 in the (numerator)over top of a square root of 7 minus a square root of 5 in the denominator
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1/(sqrt(7) - sqrt(5))
Multiply numerator and denominator by sqrt(7) + sqrt(5) to get:
= [sqrt(7) + sqrt(5)] / [7-5]
= [sqrt(7) + sqrt(5)]/2
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Cheers,
Stan H.
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