SOLUTION: Could use any help available. Thanks 5i/3-i
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-> SOLUTION: Could use any help available. Thanks 5i/3-i
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Algebra: Radicals -- complicated equations involving roots
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Question 129386
:
Could use any help available. Thanks
5i/3-i
Answer by
stanbon(75887)
(
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):
You can
put this solution on YOUR website!
5i/3-i
---------
Multiply numerator and denominator by 3+i to get:
[5i(3+i)] / [(3-i)(3+i)]
= (-5+15i) / (10)
= [5(-1+3i)]/10
= (-1+3i)/2
= (-1/2) + (3/2)i
=============================
Cheers,
Stan H.