SOLUTION: 2x^2+2x=4

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Question 119126: 2x^2+2x=4
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2%2B2x=4 Start with the given equation


2x%5E2%2B2x-4=0 Subtract 4 from both sides.


2%28x%2B2%29%28x-1%29=0 Factor the left side


Now set each factor equal to zero:
x%2B2=0 or x-1=0

x=-2 or x=1 Now solve for x in each case


So our answer is
x=-2 or x=1


Notice if we graph y=2x%5E2%2B2x-4 we can see that the roots are x=-2 and x=1 . So this visually verifies our answer.


+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%2C+2x%5E2%2B2x-4%29+