SOLUTION: The perimeter of a rectangular city lot was 420 feet. The lot was divided into two equal lots having the same width and half the length of the original lot. Find the dimensions of
Algebra ->
Radicals
-> SOLUTION: The perimeter of a rectangular city lot was 420 feet. The lot was divided into two equal lots having the same width and half the length of the original lot. Find the dimensions of
Log On
Question 1114419: The perimeter of a rectangular city lot was 420 feet. The lot was divided into two equal lots having the same width and half the length of the original lot. Find the dimensions of the smaller lots if their perimeters were 260 feet each. Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! .
.
.
.
Originally,
1.
Then after the split,
2.
Subtracting 2 from 1,
Now use either equation to solve for W.
.