SOLUTION: Given that √({{{ b/a }}} √ {{{ b/a }}} √ {{{ b/a }}}) = {{{ (b/a)^x }}} , where a, b > 0, find the rational number x. (That's √(b/a) inside another square r

Algebra ->  Radicals -> SOLUTION: Given that √({{{ b/a }}} √ {{{ b/a }}} √ {{{ b/a }}}) = {{{ (b/a)^x }}} , where a, b > 0, find the rational number x. (That's √(b/a) inside another square r      Log On


   



Question 1104116: Given that √(+b%2Fa++b%2Fa++b%2Fa+) = +%28b%2Fa%29%5Ex+ , where a, b > 0, find the rational number x. (That's √(b/a) inside another square root, which is inside another square root, by the way)
Answer by josgarithmetic(39617) About Me  (Show Source):